What is the total active motion (TAM) of an individual's index finger if the measurements are MCP 0-45, PIP 10-60, and DIP 10-40?

What is the total active motion (TAM) of an individual's index finger if the measurements are MCP 0-45, PIP 10-60, and DIP 10-40?

• A. 100 degrees
• B. 115 degrees
• C. 125 degrees
• D. 135 degrees

Answer: (C)

To calculate the total active motion (TAM) of an individual's index finger, you need to assess the range of motion at each joint and then sum those ranges of motion. The TAM is determined by the formula: TAM = (MCP flexion) + (PIP flexion) + (DIP flexion) - 1 (for the full extension of the finger). In your question, the ranges of motion for the index finger are provided as: - MCP: 0 to 45 degrees, which is a total of 45 degrees of flexion. - PIP: 10 to 60 degrees, yielding a total of 50 degrees of flexion (60 - 10). - DIP: 10 to 40 degrees, which gives us 30 degrees of flexion (40 - 10). Now, we add these values together: - MCP flexion: 45 degrees - PIP flexion: 50 degrees - DIP flexion: 30 degrees Total = 45 + 50 + 30 = 125 degrees. This total is then valid without the need to subtract for full extension since we are dealing with the flexion values directly in this context. Therefore, the total

To calculate the total active motion (TAM) of an individual's index finger, you need to assess the range of motion at each joint and then sum those ranges of motion. The TAM is determined by the formula:

TAM = (MCP flexion) + (PIP flexion) + (DIP flexion) - 1 (for the full extension of the finger).

In your question, the ranges of motion for the index finger are provided as:

• MCP: 0 to 45 degrees, which is a total of 45 degrees of flexion.

• PIP: 10 to 60 degrees, yielding a total of 50 degrees of flexion (60 - 10).

• DIP: 10 to 40 degrees, which gives us 30 degrees of flexion (40 - 10).

Now, we add these values together:

• MCP flexion: 45 degrees

• PIP flexion: 50 degrees

• DIP flexion: 30 degrees

Total = 45 + 50 + 30 = 125 degrees.

This total is then valid without the need to subtract for full extension since we are dealing with the flexion values directly in this context. Therefore, the total